A Coefficient Decomposition

Problem

In ABC\triangle ABC, the sides opposite A,B,CA, B, C are a,b,ca, b, c. A point MM lies on side ABAB, and a point PP on line CMCM satisfies

CP=CAbcosA+CBacosB.\overrightarrow{CP} = \frac{\overrightarrow{CA}}{b\cos A} + \frac{\overrightarrow{CB}}{a\cos B}.

Given CM=c2\left|\overrightarrow{CM}\right| = \dfrac{c}{2} and a2+b2=22aba^2 + b^2 = 2\sqrt{2}ab, find CC.

Answer

Solution

Difficulty7/10
Topicstrigonometry, Law of Cosines, Triangle Geometry, vectors

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