A Double-Root Cubic

Problem

Let f(x)=(x1)2(x4)f(x) = (x - 1)^2(x - 4). Determine, with proof, which of the following are true:

1. x=1x = 1 is a local minimum point of f(x)f(x); 2. f(2+x)+f(2x)=4f(2 + x) + f(2 - x) = -4 for all xx; 3. the solution set of 4<f(2x1)<0-4 < f(2x - 1) < 0 is {x1<x<2}\{x \mid 1 < x < 2\}; 4. for 0<x<π20 < x < \dfrac{\pi}{2}, f(sinx)>f(sin2x)f(\sin x) > f\left(\sin^2 x\right).

Answer

Solution

Difficulty6/10
Topicsfunctions, Extrema, calculus, Monotonicity, Polynomials, Symmetry

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