A Half-Angle Relation

Problem

In ABC\triangle ABC, AC=5AC = 5 and

1tanA2+1tanC25tanB2=0.\frac{1}{\tan\frac{A}{2}} + \frac{1}{\tan\frac{C}{2}} - \frac{5}{\tan\frac{B}{2}} = 0.

Find BC+ABBC + AB.

Answer

Solution

Difficulty7/10
Topicstrigonometry, Trigonometric Identities, Triangle Geometry

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