A Log-Squeezed Sum

Problem

A positive sequence has a1=1a_1 = 1 and

an+1=anan2+1.a_{n+1} = \frac{a_n}{\sqrt{a_n^2 + 1}}.

Prove that

ln⁡(n+1)<a1a2+a2a3+⋯+anan+1<ln⁡(2n3+1)+12.\ln(n+1) < a_1a_2 + a_2a_3 + \cdots + a_na_{n+1} < \ln\left(\frac{2n}{3} + 1\right) + \frac12.

Answer

Solution

Difficulty8/10
Topicssequences, Logarithms, AM-GM, Telescoping, inequality

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