A Nonnegative Minimum

Problem

Let a>0a > 0 and f(x)=(1ax)(ex1)f(x) = (1 - ax)\left(\mathrm{e}^x - 1\right).

1. If a=1a = 1, prove that f(x)<ln(x+1)f(x) < \ln(x+1) for x>0x > 0. 2. If h(x)=ln(x+1)f(x)h(x) = \ln(x+1) - f(x) has a local minimum point x0x_0, prove that f(x0)0f(x_0) \geqslant 0.

Answer

Solution

Difficulty7/10
Topicsfunctions, Extrema, calculus, Monotonicity, Casework

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