A Polar Collinearity

Problem

Consider the hyperbola E ⁣:x2a2y2b2=1E \colon \dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1 and a point M(x0,y0)M(x_0, y_0) not on EE with x0y00x_0y_0 \neq 0. Let N(λx0,λy0)N(\lambda x_0, \lambda y_0), where

1λ=x02a2y02b2.\frac{1}{\lambda} = \frac{x_0^2}{a^2} - \frac{y_0^2}{b^2}.

A line ll through NN meets EE at AA and BB; the line through BB with slope b2x0a2y0\dfrac{b^2x_0}{a^2y_0} meets EE again at CC. Prove that A,M,CA, M, C are collinear.

Answer

Solution

Difficulty9/10
TopicsPole and Polar, Parametrization, conic sections, analytic geometry

Whiteboard

Your sketch is saved only in this browser. To share it, export your drawing as an image (whiteboard menu → Export as → PNG), then upload that image in the comments below.

Discussion

Ask questions, share alternate solutions, and use LaTeX freely.

0 comments
Log in to join the discussion.

No comments yet.