A Radical Axis Chord

Problem

Let ABAB be a chord of a circle ω\omega, and let PP be a point on the chord ABAB. A circle ω1\omega_1 passes through PP and is internally tangent to ω\omega at AA; a circle ω2\omega_2 passes through PP and is internally tangent to ω\omega at BB. The circles ω1\omega_1 and ω2\omega_2 meet at PP and QQ, and the line PQPQ meets ω\omega at points XX and YY. Given AP=5AP=5, PB=3PB=3, XY=11XY=11, write PQ2PQ^2 as a fraction mn\dfrac mn in lowest terms. Find m+nm+n.

Answer

Solution

Difficulty8/10
Topicsplane geometry, Reflection, Circles, Power of a Point

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