A Seventh-Power Trig Equation

8/10functionstrigonometryMonotonicity

Problem

Solve over the reals:

sin7x+1cos3x=cos7x+1sin3x.\sin^7 x + \frac{1}{\cos^3 x} = \cos^7 x + \frac{1}{\sin^3 x}.

Answer

Solution

Difficulty8/10
Topicsfunctions, trigonometry, Monotonicity

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