A Slope Ratio Maximum

8/10ExtremaAM-GManalytic geometry

Problem

The three lines

l1:y=k1x,l2:y=k2x+1,l3:y=k3(x1)l_1:y=k_1x,\qquad l_2:y=k_2x+1,\qquad l_3:y=k_3(x-1)

bound a triangle of area 44, and k1<0<k2<k3k_1<0<k_2<k_3. Find the maximum value of k2k3\dfrac{k_2}{k_3}.

Answer

Solution

Difficulty8/10
TopicsExtrema, AM-GM, analytic geometry

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