A Strange Operation

★ 5/10functions Substitution algebra Functional Equations

Problem

An operation $\&$ on real numbers satisfies, for all reals $x, y, z$ ,

x \& (y \& z) = (x \& y) + z, \qquad x \& x = 0.

Compute $2000 \& 2022$ .

Answer

Solution

Difficulty	5/10
Topics	functions, Substitution, algebra, Functional Equations

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