A Two-Parameter Minimum

Problem

Let aa and bb be real numbers, and let f(x)=a2x21+axf(x)=|a^2x^2-1|+ax. Suppose that

f(x)xfor all x[b,+).f(x)\geqslant |x|\quad\text{for all }x\in[b,+\infty).

Find the minimum value of

m=a2b2+(b12)2.m=a^2b^2+\left(b-\frac 12\right)^2.

Answer

Solution

Difficulty8/10
Topicsfunctions, Substitution, Absolute Value, inequality, Casework

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