A Vector-Locked Triangle

Problem

In ABC\triangle ABC, the sides opposite A,B,CA, B, C are a,b,ca, b, c, and

BA+BC=2,ABAC=2.\left|\overrightarrow{BA} + \overrightarrow{BC}\right| = 2, \qquad \overrightarrow{AB}\cdot\overrightarrow{AC} = 2.

Find the minimum value of b2abb^2 - ab.

Answer

Solution

Difficulty8/10
Topicstrigonometry, Law of Cosines, Completing the Square, Triangle Geometry, vectors

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