An Adventitious Angle

Problem

In ABC\triangle ABC, AB=ACAB=AC, and a point PP satisfies

BAP=20,ABP=10,PAC=60.\angle BAP=20^\circ,\qquad \angle ABP=10^\circ,\qquad \angle PAC=60^\circ.

Find APC\angle APC.

Answer

Solution

Difficulty8/10
Topicsplane geometry, Inscribed Angle, Reflection, Triangle Geometry

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