An Angle Bisected by a Horizontal

Problem

The ellipse C:x2a2+y2b2=1C: \dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} = 1 (a>b>0a > b > 0) has eccentricity 32\dfrac{\sqrt3}{2} and passes through P(2,−1)P(2, -1).

1. Find the equation of CC. 2. Let QQ on CC be such that PQPQ is horizontal. Two lines through PP meet CC at A(x1,y1)A(x_1,y_1) and B(x2,y2)B(x_2,y_2). If PQPQ bisects ∠APB\angle APB, prove that the slope of ABAB is constant, and find it.

Answer

Solution

Difficulty7/10
TopicsInscribed Angle, Affine Transformation, conic sections, analytic geometry

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