An Angle-Bisector Foot

Problem

Let OO be the origin and let F1,F2F_1, F_2 be the left and right foci of the hyperbola C ⁣:x2a2−y2b2=1C \colon \dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1 (a>0a > 0, b>0b > 0) with eccentricity 62\dfrac{\sqrt{6}}{2}. Let P(x1,y1)P(x_1, y_1) be a point on the right branch other than the vertex. The perpendicular from F2F_2 to the bisector of ∠F1PF2\angle F_1PF_2 has foot MM, and ∣MO∣=2|MO| = \sqrt{2}. If a point TT on CC satisfies F1T→⋅F2T→=5\overrightarrow{F_1T}\cdot\overrightarrow{F_2T} = 5, find the sum of the distances from TT to the two asymptotes of CC.

Answer

Solution

Difficulty7/10
TopicsReflection, conic sections, analytic geometry, Triangle Geometry

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