Claims About a Cubic Iteration

Problem

A sequence {an}\{a_n\} satisfies an+1=14(an6)3+6a_{n+1}=\dfrac 14(a_n-6)^3+6 (nNn\in\mathbb N^{*}). Determine, with proof, which of the following claims are true.

1. When a1=3a_1=3, {an}\{a_n\} is decreasing, and there is a constant M0M\leqslant 0 with an>Ma_n>M for all nn. 2. When a1=5a_1=5, {an}\{a_n\} is increasing, and there is a constant M6M\leqslant 6 with an<Ma_n<M for all nn. 3. When a1=7a_1=7, {an}\{a_n\} is decreasing, and there is a constant M>6M>6 with an>Ma_n>M for all nn. 4. When a1=9a_1=9, {an}\{a_n\} is increasing, and there is a constant M>0M>0 with an<Ma_n<M for all nn.

Answer

Solution

Difficulty8/10
TopicsMonotonicity, Recursion, sequences, Casework

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