Cotangents in an Acute Triangle

Problem

In an acute triangle ABCABC,

2sin2A+sin2B=2sin2C.2\sin^2 A + \sin^2 B = 2\sin^2 C.

Find the minimum value of

1tanA+1tanB+1tanC.\frac{1}{\tan A} + \frac{1}{\tan B} + \frac{1}{\tan C}.

Answer

Solution

Difficulty7/10
Topicstrigonometry, Trigonometric Identities, AM-GM, inequality

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