Extremes as Zeros

Problem

Let f(x)=1x−x+2aln⁡xf(x) = \dfrac{1}{x} - x + 2a\ln x, where aa is a real number.

1. If a=12a = \dfrac{1}{2}, find the equation of the tangent line to y=f(x)y = f(x) at (1,f(1))(1, f(1)). 2. Find the intervals on which f(x)f(x) is monotonic, discussing all cases. 3. Let g(x)=ln⁡x−bx−cx2g(x) = \ln x - bx - cx^2. Suppose the two extreme points x1<x2x_1 < x_2 of f(x)f(x) are exactly the two zeros of g(x)g(x), and the range of

y=(x1−x2) g′ ⁣(x1+x22)y = (x_1 - x_2)\,g'\!\left(\frac{x_1 + x_2}{2}\right)

is [ln⁡2−23,+∞)\left[\ln 2 - \dfrac{2}{3}, +\infty\right). Find the range of possible values of aa.

Answer

Solution

Difficulty8/10
Topicsfunctions, Extrema, calculus, Monotonicity, Vieta's Formulas

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