Growth of a Recursion

Problem

Let a1=1a_1 = 1, a2=8a_2 = 8, and

an+1=an1+4nan(n=2,3,).a_{n+1} = a_{n-1} + \frac{4}{n}a_n \qquad (n = 2, 3, \ldots).

1. Prove that there exists c>0c > 0 with ancn2a_n \leqslant cn^2 for all nn. 2. Prove that an+1an4n+3a_{n+1} - a_n \leqslant 4n + 3 for all nNn \in \mathbb{N}^*.

Answer

Solution

Difficulty8/10
TopicsRecursion, sequences, Induction, Telescoping, inequality

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