Perpendicular Tangents From a Circle

Problem

The ellipse Γ:x2a2+y2b2=1\Gamma: \dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} = 1 (a>b>0a > b > 0) has top vertex C(0,1)C(0, 1), and the circle centered at CC with radius 433\dfrac{4\sqrt3}{3} is tangent to Γ\Gamma.

1. Find the equation of Γ\Gamma. 2. A point PP on the circle sends two tangents to Γ\Gamma, touching at AA and BB. If PAPBPA \perp PB, find the coordinates of PP.

Answer

Solution

Difficulty7/10
TopicsExtrema, Tangent Circle, Circles, conic sections, analytic geometry

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