Two Zeros and a Bounded Minimum

9/10ExtremacalculusMonotonicityAM-GM

Problem

Let a(0,1)a \in (0, 1), and define

f(x)=xax(a+1)lnx+a1,g(x)=x+ax1lnx.f(x) = x - \frac{a}{x} - (a+1)\ln x + a - 1, \qquad g(x) = \frac{x+a}{x-1}\ln x.

1. Prove that f(x)f(x) has exactly 22 zeros. 2. For x(0,1)x \in (0, 1), prove that g(x)g(x) attains a minimum value h(a)h(a), and that 0<h(a)<20 < h(a) < 2.

Answer

Solution

Difficulty9/10
TopicsExtrema, calculus, Monotonicity, AM-GM

Whiteboard

Your sketch is saved only in this browser. To share it, export your drawing as an image (whiteboard menu → Export as → PNG), then upload that image in the comments below.

Discussion

Ask questions, share alternate solutions, and use LaTeX freely.

0 comments
Log in to join the discussion.

No comments yet.