A Cevian of Length One

Problem

In △ABC\triangle ABC, B=2π3B = \dfrac{2\pi}{3} and BC>ABBC > AB. A point DD satisfies AD→=2DC→\overrightarrow{AD} = 2\overrightarrow{DC} and BD=1BD = 1. Find the range of possible values of ACAC.

Answer

Solution

Difficulty7/10
Topicstrigonometry, Law of Cosines, Monotonicity, inequality, Triangle Geometry, vectors

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