A Circle Fraction Minimum

Problem

Real numbers x,yx, y satisfy

x2+y210x10y+45=0.x^2 + y^2 - 10x - 10y + 45 = 0.

Find the minimum value of

2x2xyyx.\frac{2x^2 - xy - y}{x}.

Answer

Solution

Difficulty7/10
TopicsParametrization, Circles, Trigonometric Identities, analytic geometry, inequality

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