A Cotangent Symmetry

Problem

The angles of ABC\triangle ABC satisfy

sinAcotB+sinBcotA=2sinC2.\sin A\cot B + \sin B\cot A = 2\sin\frac{C}{2}.

Prove that A=BA = B.

Answer

Solution

Difficulty8/10
Topicstrigonometry, Substitution, Trigonometric Identities, Triangle Geometry

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