A Product Below me2m\mathrm{e}^2

Problem

The function f(x)=lnx+mx3f(x) = \ln x + \dfrac{m}{x} - 3 has two zeros.

1. Find the range of possible values of mm. 2. Let a,ba, b be the two zeros of f(x)f(x). Prove that

ab<me2.ab < m\mathrm{e}^2.

Answer

Solution

Difficulty7/10
Topicsfunctions, Extrema, calculus, Substitution, Monotonicity, inequality

Whiteboard

Your sketch is saved only in this browser. To share it, export your drawing as an image (whiteboard menu → Export as → PNG), then upload that image in the comments below.

Discussion

Ask questions, share alternate solutions, and use LaTeX freely.

0 comments
Log in to join the discussion.

No comments yet.