Exponentials Meet Recurrences

★ 6/10LimitsRecursionsequencesLogarithms

Problem

A sequence {an}\{a_n\} satisfies

4an+2+41+an+1−12⋅4an=0.4^{a_{n+2}} + 4^{1 + a_{n+1}} - 12 \cdot 4^{a_n} = 0.

Find

lim⁡n→+∞ann.\lim_{n \to +\infty} \frac{a_n}{n}.

Answer

Solution

Difficulty6/10
TopicsLimits, Recursion, sequences, Logarithms

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