Heights and a Hidden Identity

Problem

In ABC\triangle ABC, the altitudes to sides a,b,ca, b, c have lengths ha,hb,hch_a, h_b, h_c, and

3ahabhb+6chc=6.3\cdot\frac{a}{h_a} - \frac{b}{h_b} + 6\cdot\frac{c}{h_c} = 6.

1. If SS is the area of the triangle, prove that S=112(3a2b2+6c2)S = \dfrac{1}{12}\left(3a^2 - b^2 + 6c^2\right). 2. Express sin(A+π4)\sin\left(A + \dfrac{\pi}{4}\right) in terms of bb and cc, and find AA. 3. Based on the structure of this problem, formulate an analogous statement about triangles of your own design, and prove it.

Answer

Solution

Difficulty8/10
Topicstrigonometry, Law of Cosines, AM-GM, Triangle Geometry

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