Last Two Digits of a Term

Problem

A sequence {an}\{a_n\} satisfies a1=1a_1 = 1, a2=2a_2 = 2, and for k∈N+k \in \mathbb{N}^+,

a2k+1=a2k2a2k−1,a2k+2=2a2k+1−a2k.a_{2k+1} = \frac{a_{2k}^2}{a_{2k-1}}, \qquad a_{2k+2} = 2a_{2k+1} - a_{2k}.

Find the last two digits of a2022a_{2022}.

Answer

Solution

Difficulty6/10
Topicsnumber theory, Recursion, Modular Arithmetic, sequences, Induction

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