A Rotating 30-Degree Angle in an Isosceles Right Triangle

Problem

figure

In the isosceles right triangle OPQOPQ, POQ=90\angle POQ = 90^\circ and OP=22OP = 2\sqrt{2}. A point MM lies on the segment PQPQ.

1. If OM=5OM = \sqrt{5}, find the length PMPM. 2. A point NN lies on the segment MQMQ with MON=30\angle MON = 30^\circ. For what value of POM\angle POM is the area of OMN\triangle OMN smallest, and what is that smallest area?

Answer

Solution

Difficulty5/10
Topicsplane geometry, Law of Sines, trigonometry, Extrema, Law of Cosines

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