Three Zeros of an Absolute Log

Problem

Let a≠0a \neq 0 be real and

f(x)=∣ln⁡x∣+ax.f(x) = |\ln x| + \frac{a}{x}.

1. If a=1a = 1, find the minimum value of f(x)f(x). 2. Discuss the monotonicity of f(x)f(x). 3. If f(x)f(x) has exactly three distinct zeros x1,x2,x3x_1, x_2, x_3, prove that

x1+x2+x3>2a2−4a+11−a.x_1 + x_2 + x_3 > \frac{2a^2 - 4a + 1}{1 - a}.

Answer

Solution

Difficulty8/10
Topicsfunctions, Log Mean Inequality, calculus, Absolute Value, Monotonicity

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