An Acute Cotangent Window

Problem

In an acute triangle ABCABC, the sides opposite A,B,CA, B, C are a,b,ca, b, c, and

b(a+c)sin⁡A=1cos⁡(B+3π2).\frac{b}{(a+c)\sin A} = \frac{1}{\cos\left(B + \dfrac{3\pi}{2}\right)}.

1. Prove that cos⁡B=2cos⁡2A−1\cos B = 2\cos^2 A - 1. 2. If m<1tan⁡A−1tan⁡B<nm < \dfrac{1}{\tan A} - \dfrac{1}{\tan B} < n holds for all such triangles, find the minimum value of n−mn - m.

Answer

Solution

Difficulty8/10
TopicsLaw of Sines, trigonometry, Extrema, Trigonometric Identities, Triangle Geometry

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